Divide a circle into 'n' parts and what is the geometry of each part?
Solution:: Suppose if a line is drawn through the centre of a circle then it will divide it into 2 equal parts and if you draw 2 lines at right angles passing through the centre then it will divide into 4 equal parts...and for 3 lines at 60° each then 6 parts and it goes on...
For odd number of parts what we have to do??
It's simple as it sounds because initially we used angle concept.. The same can be applied here also.. If we want 3 equal parts then the angle at the centre should be divided by 3 , for 5 parts the angle at the centre is divided by 5 and so on..
If you want to divide into 'n' parts then the angle at the centre is divided by 'n'.
The angle of each part is (360/n)° and all the parts are sectors with equal area.
Let's see this diagrammatically...
Solution:: Suppose if a line is drawn through the centre of a circle then it will divide it into 2 equal parts and if you draw 2 lines at right angles passing through the centre then it will divide into 4 equal parts...and for 3 lines at 60° each then 6 parts and it goes on...
For odd number of parts what we have to do??
It's simple as it sounds because initially we used angle concept.. The same can be applied here also.. If we want 3 equal parts then the angle at the centre should be divided by 3 , for 5 parts the angle at the centre is divided by 5 and so on..
If you want to divide into 'n' parts then the angle at the centre is divided by 'n'.
The angle of each part is (360/n)° and all the parts are sectors with equal area.
Let's see this diagrammatically...
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